A ray of light strikes the midpoint of one face of an equiangular (60 degree -60

Question

A ray of light strikes the midpoint of one face of an equiangular (60 degree -60 degree -60 degree) glass prism (n = 1.5) at an angle of incidence of 36.4 degree. Trace the path of the light ray through the glass, and find the angles of incidence and refraction at each surface. First surface: theta_incidence = theta_refraction Second surface: theta_incidence = theta_refraction = If a small fraction of light is also reflected at each surface, find the angles of reflection at the surfaces. theta_reflection = (first surface) theta_reflection = (second surface)

Explanation / Answer

from snells law

n1 sin1 = n2 sin2

the angle of refraction at the left surfaceis given by

1r = sin-1(nair sin1i / nglass)

1r   =sin-1 (1 sin 36.4/ 1.5)

1r = 23.3 deg

Let t the angles and as

= 90 -1r = 90– 23.3   = 66.69 deg

= 180 - 60 -66.69 = 53.31 deg

therefore the angle of incidence at the second surface will be

2i = 90 - = 90- 53.31 = 36.69 deg
      
angle of refraction will be 2r = sin-1(nglass sin2i / nair)

2r = sin-1(1.5 sin 36.69 / 1.0) = 63.66 deg

      
(b)
   as the angle of incidence is equal to the angle of reflection

   (1)reflection =1i = 23.34 deg
                   
   (1)reflection =2 = 36.69 deg

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