A raw fish fillet has a composition of 20% solid,10% oil, and 70% moisture. The

Question

A raw fish fillet has a composition of 20% solid,10% oil, and 70% moisture. The fish fillet is cooked. During thecooking process half the oil is driven off. If the final (cooked)moisture percentage is 50, what is the cooked weight of a filletwhose weight was 1 pound (454 grams)?

1 pound = 454 grams

What I have so far is:

20% solidinitial               5% oil final

10% oilinitial                   50% moisture final

70% moisture initial

this is pretty much basic algebra or basicphysics but it's been a while since i 've done this so i don'tremember the formulas or how set the problems up to solve them so ineed some help.

Explanation / Answer

initial      values solid                              oil                           moisture 9.08gram                      4.54gram                   440.38g after cooking 9.09gram                        2.27g(half)     let this be x cooked weight =11.35+x as per the problem     the final (cooked) moisture percentage is 50, so 2x=11.35+x solving x=11.35gram so cooked weight=22.70gram=22.7/454=0.05pound

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.