A ray enters a right-angle optical glass prism parallel to base as shown in the

Question

A ray enters a right-angle optical glass prism parallel to base as shown in the figure. What is a maximum angle theta at the base the prism, for which the ray experiences total internal reflection in the prism? The refraction index of glass is n = 1.54. An object of 3 cm height is placed 60 cm away from a 40-cm-focal length concave minor. a) Find the distance between the image and the mirror. b) What is the height of the image? c) Is the object upright or turned over? Explain your answer. (The answer without explanation will not be given any credit.)

Explanation / Answer

Problem 6]

Use the lens formula, 1/f = 1/v + 1/u

object distance = u = 60 cm

focal length = f = 40 cm

so, 1/40 = 1/v + 1/60

=> v = 120 cm

therefore, the distance between the image and the mirror will be: v = 120 cm.

b] Magnification = m = - v/u = - 120/60 = - 2

therefore, the height of the image will be: H = 2 x 3 = 6cm

c] Since the object is placed beyond the focal length of the concave mirror but before the radius of curvature of the mirror (2f = 80 cm), the image formed will be real and inverted (turned over).

Note: Problem 5 requires the image where the angles of the right-angle prism are specified.

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