215/2018 11:55 PM 87.5/100 1/31/2018 03:05 PM Print Cakulatr bd Periodic Table e

Question

215/2018 11:55 PM 87.5/100 1/31/2018 03:05 PM Print Cakulatr bd Periodic Table estion 3 ol 17 Consider this reaction data: If you were going to graphically determine the activation energy this reaction, what points would you plot? A products point 1:n 325 0.378 725 0.831 To avoid rounding errors, use at leas three signiicant figures in ail values pont 2: 11 Determine the rise, run, and slope of the line formed by these points rise Number What is the activation energy of this reaction? J/ mol FS F6 3 4

Explanation / Answer

We need to plot lnK on y axis and 1/T on x axis
k = 0.378
ln k = ln (0.378) = -0.97286
T = 325.0
1/T = 0.00308


point 1 is:
x = 0.00308
y = -0.97286


k = 0.831
ln k = ln (0.831) = -0.18513
T = 725.0
1/T = 0.00138


point 2 is:
x = 0.00138
y = -0.18513


----------------------------------------------------------------------------
rise = (y1-y2) = -0.97286 - -0.18513 = -0.78774
rise = (X1-X2) = 0.00308 - 0.00138 = 0.0017
slope = rise/run
= -0.78774/0.0017
= -464.0255
----------------------------------------------------------------------------
use
slope = - Ea/R
= -464.0255 = -Ea/8.314
Ea = 3858 J/mol
Answer: 3858 J/mol

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