21/2017 10:00 PM 487.7/100 Gradeb Print Calalator Perodc Table stion 13 of 19 Sa

Question

21/2017 10:00 PM 487.7/100 Gradeb Print Calalator Perodc Table stion 13 of 19 Sapling Learming Belore Collisian Aller 1.85v aet V. The mass of one particle is m, and the ss of the other particle is nm, where n is just a unitless number. Snapshots of the system before, and after the elastic collision are shown above. during Ater the colision the first particle moves in the exact opposle direction with speed 1.85v, and the speed of After the lision the first particle moves in the exad the second particle is unknown What is the value of n? Number Tools O Previous Check Answer 0 Next Exit Hint F10

Explanation / Answer

from conservation of momentum we know

Pi = Pf

m v - nm v = m x 1.85 v + n m v(final)

m gets cancelled both sides

v - n v = 1.85 v + n v(final)

2.85 v - n v = n v(final)

v(final) = (2.85 v - nv)/n

from conservation of energy:

Ei = Ef

1/2 m v^2 + 1/2 nm v^2 + 1/2 m (1.85v)^2 + 1/2 nm v(final)^2

v^2 + nv^2 = 3.423 v^2 + n v(final)^2

n v(final)^2 = n v^2 - (2.423) v^2

putting the value of v(final)

n [(2.85 v - nv)/n]^2 = n v^2 - 2.423 v^2

8.123 v^2 + n^2 v^2 - 5.7 n v^2 = n^2 v^2 - 2.423 n v^2

8.123 v^2 - 5.7 n v^2 + 2.423 n v^2 = 0

8.123 - 5.7 n + 2.423 n = 0

n = 8.123/3.277 = 2.48

Hence, n = 2.48

Related Questions

Navigate

• Browse (All)
• Browse 2
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.