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ID: 571849 • Letter: D
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Details !all mechnisms all.! !!no ugly writing!!thanks!!or thumbs down!!and report abuse to chegg!stop ur expert!Please help with this question, thanks!
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Explanation / Answer
4. (a) 18O nucleus:
The mass no. (A) = 18, i.e. even no.
The atomic no. (Z) = 8, i.e. even no.
Rule: If both A and Z of a nucleus are even, then the nucleus is NMR-inactive.
Therefore, the 18O nucleus has zero spin.
(b) 10B nucleus:
The mass no. (A) = 10, i.e. even no.
The atomic no. (Z) = 5, i.e. odd no.
Rule: If a nucleus has even A value and odd Z value, then the nucleus is NMR active with integral spin.
Therefore, the 10B nucleus has integral spin.
(c) 13C nucleus:
The mass no. (A) = 13, i.e. odd no.
Rule: If a nucleus has odd A value, then irrespective of its Z value, the nucleus is NMR active with half-integral spin.
Therefore, the 13C nucleus has half-integral spin.
(d) 14N nucleus:
The mass no. (A) = 14, i.e. even no.
The atomic no. (Z) = 7, i.e. odd no.
Rule: If a nucleus has even A value and odd Z value, then the nucleus is NMR active with integral spin.
Therefore, the 14N nucleus has integral spin.
(e) 19F nucleus:
The mass no. (A) = 19, i.e. odd no.
Rule: If a nucleus has odd A value, then irrespective of its Z value, the nucleus is NMR active with half-integral spin.
Therefore, the 19F nucleus has half-integral spin.
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