The formula for butyric acid is CH 3 CH 2 CH 2 COOH . Jessica and Lovely want to

Question

The formula for butyric acid is CH3CH2CH2COOH . Jessica and Lovely want to know how many oxygen atoms are in 0.080 moles of acetic acid.

1.56 x 1023 atoms

3.6 x 1022 atoms

4.0 x 10-24 atoms

9.6 x 1022 atoms

60 atoms

2.8 x 1023 atoms

The formula for butyric acid is CH3CH2CH2COOH . Jessica and Lovely want to know how many oxygen atoms are in 0.080 moles of acetic acid.

1.56 x 1023 atoms

3.6 x 1022 atoms

4.0 x 10-24 atoms

9.6 x 1022 atoms

60 atoms

2.8 x 1023 atoms

1.56 x 1023 atoms

3.6 x 1022 atoms

4.0 x 10-24 atoms

9.6 x 1022 atoms

60 atoms

2.8 x 1023 atoms

Explanation / Answer

we have below equation to be used:

number of molecules of CH3CH2CH2COOH = number of mol * Avogadro’s number

= 8*10^-2 * 6.022*10^23 molecules

= 4.818*10^22 molecules

1 molecule of CH3CH2CH2COOH has 2 O

So,

number of O = 2*number of molecules of CH3CH2CH2COOH

= 2*4.818*10^22

= 9.6*10^22 atoms

Answer: 9.6*10^22 atoms

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