A solution is 0.010 M is each of Pb(NO_2)_2, Mn(NO_2)_2, and Zn(NO_2)_3. Solid N
ID: 528125 • Letter: A
Question
A solution is 0.010 M is each of Pb(NO_2)_2, Mn(NO_2)_2, and Zn(NO_2)_3. Solid NaOH in added until the [OH^-] of the solution is 3.0 times 10^-6 M, K_sp = 2.8 times 10^-56 for Pb(OH)_2, 4.5 times 10^-14 for Ma(OH)_2, and 4.5 times 10^-17 for Zn(OH)_2. Which of the following statements is true? No precipitate will form. Only Zn(OH)_2 will precipitate. Only Mn(OH)_2 will precipitate. Only Zn(OH)_2 and Pb(OH)_2 will precipitate All three hydroxides will precipitate. Given the equilibrium constants for the following reactions 4Cu(s) + O_2(g) rlhar 2Cu_2O(s), K_1 2CuO(s) rlhar Cu_2O(s) + 1/2 O_2(g), K_2 What is K for the system 2 Cu(s) + O_2(g) rlhar 2CuO(s) equivalent to? K_1 times K_2 K_1^1/2 times K_2 K_1^1/2/K_2 K_2^1/2/K_1 K_1 times K_2^1/2 The reaction mechanism for the decomposition of H_2O_2 is H_2O_2 + I^- rightarrow H_2O + IO^- slow H_2O_2 + IO^- rightarrow H_2O + O_2 + I^- fast Which of the following statements is TRUE? The reaction is first order with respect to [I^-]. The reaction is first order with respect to [H_2O_2]. I^- is a catalyst. 1 only 2 only 3 only 1 and 3 only 1, 2, and 3 Which of the following processes would be expected to have a positive Delta S value? 2H_2(g) + O_2(g) rightarrow 2H_2O(g) I_2(g) rightarrow I_2(s) 2ClBr(g) rightarow Cl_2(g) + Br_2(g) NH_4HS(s) rightarrow NH_3(g) + H_2S(g) 2NO(g) + O_2(g) rightarrow 2NO_2(g)Explanation / Answer
30. True statements about selective precipitation reaction would be,
c.
31. The equilibrium constant by Hess's law from the given two equations would be,
c.
32. True statement about reaction,
c.
33. Positive dS would be expected for,
d.
Related Questions
Hire Me For All Your Tutoring Needs
Integrity-first tutoring: clear explanations, guidance, and feedback.
Drop an Email at
drjack9650@gmail.com
drjack9650@gmail.com
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.