The restriction enzyme Mbo1 https://www.neb.com/products/r0147-mboi cuts the seq

Question

The restriction enzyme Mbo1 https://www.neb.com/products/r0147-mboi cuts the sequence GATC.

1. If the digestion is complete how many fragments do you expect will be generated from the human genome of 3 billion base pairs?

2. If the digestion is only 1% complete - that is only 1/100 potential sites are cleaved, how many fragments do you expect will be generated from the humnan genome of 3 billion base pairs?

3. For each case a and b what is the concentration of the Mbo1 generated ends in the nucleus?

Explanation / Answer

1. The expected number of fragments when cut with Mbo 1 in the human genome of 3 billion base pairs is 1.17 x 107.

The length of the restriction site is 4 base pairs. Therefore, the site GATC is expected for every 44 = 256 base pairs. The total length of the human genome is given as 3 billion base pairs. Thus, there are 1.17 x 107 GATC sites in the human genome giving rise to fragments.

2. If only 1% of the total potential sites are cleaved, then the number of fragments obtained will be 1.17 x 105. (1.17 x 107/100)

The concentration of Mbo 1 would be reletively very less in case b compared to case a.

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