is the mass number of the isotope of the longest half.life. assigned temporary n
ID: 484489 • Letter: I
Question
is the mass number of the isotope of the longest half.life. assigned temporary names based on their atom ot yet assigned for element s 113, 115, 117 18. These elements are belements.com more information. 142f Chemical Reactions 4.70 A sample of oxalic acid, H2Czo., weighing 1.200 g is of iodi placed in a 100,0-mL volumetric flask, which is then filled to mass p the mark with water. What is the molarity of the solution? C 4.85 4.71 What volume of 0.120 M CuSO, is required to give ion. A solutio 0.150 mol of copper sulfate, Cusos? 4.72 How many m of 0.126 M HCIO. (perchloric in the ple of acid) are required to give 0.150 mol HCIO? 4.73 An experiment calls for 0.0353 g of potassium hydroxide, KoH. How many milliliters of 0.0176 M KOH D are required? 4.74 What is the volume (in milliliters) of 0.100 M H2SO 4.86 (sulfuric acid) containing 0.949 g H2SO4? lutio 4.75 Heme, obtained from red blood cells, binds oxy- the c gen, O2. How many moles of heme are there in 150 mL of of th 0.0019 M heme solution? 4,76 Insulin is a hormone that controls the use of glucose in the body. How many moles of insulin are required to D make up 28 mL of 0.0048 M insulin solution? 4.77 How many grams of sodium dichromate, Na,Cro, 4.8 hould be added to a 100.0 mL volumetric flask to prepare exc 0.033 M Na2Cr20, when the flask is filled to the mark with iom water? 4.78 Describe how you would prepare 2.50 x 102 mL of 4.8 0.50 M Naso. What mass (in grams) of sodium sulfate, ge Na2SO4, is needed? 4.79 You wish to prepare 0.12 M HNO, from a stock B tion of nitric acid that is 15.8 M. How many milliliters of the stock solution do you require to make up 1.00 L of M HNO3? 4.80 A chemist wants to prepare 0.75 MHCI. Commercial 4 hydrochloric acid is 12.4 M. How many milliliters of the commercial acid does the chemist require to make up 1.50 L t of the dilute acid? 4.81 A 8.50 g sample of KCI is dissolved in 660 ml ofExplanation / Answer
Q4.70
H2C2O4
m = 1.2 g
in V = 100 mL = 0.1 L
Molarity = mol / Volume
MW of acid = 90.03 g/mol
mol of acid = mass/MW = 1.2/90.03 = 0.013328
so..
M = 0.013328 / (0.1) = 0.13328 M
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