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is owLv2 | Online teaching × OwLv2] Online Teaching x C cvg.cengagenow.com/ilrn/takeAssignment/takeCovalent Activity do?locator-assignment-take&takeAssignmentSessionLocator-assignment-take; : Apps : kober portal D 2004 Saturn L300 H: web chemucsbedu -Baltimore Classificat Acute Viral Hepatitis Hepatitis A Treatme Jaundice: MedlinePl Other bookmarks Time Remaining; 1:47:53 UNIT TEST Use the References to access important values if needed for this question. 1 pt 1 pr 1 pt 1 pt 1 pt 1 pt 1 pr 1 pt 1 pt 1 pt 1 pt 1 pr 1 pt 1 pt 1 pt 1 pt Question 2 Question 3 Question 4 Question 5 Question 6 How many grams of phosphorus (P) are needed to completely consume 55.2 L of chlorine gas according to the following reaction at 25 °C and 1 atm? phosphorus (P (s)+ chlorine (gphosphorus trichloride (I) grams phosphorus (P4 Submit Answer Try Another Version 1 item attempt remaining Question 9 Question 10 Question 11 Question 12 Question 13 Question 14 Question 15 Question 16 Progress: 0/25 items Due Nov 2 at Previous Next 11:00 PM Show Hint 8:36 PM 11/2/2017

Explanation / Answer

The reaction taking place is:

P4 + 6 Cl2 —> 4 PCl3

1st find the moles of Cl2 reacting

P = 1.0 atm

V = 55.2 L

T = 25.0 oC

= (25.0+273) K

= 298 K

find number of moles using:

P * V = n*R*T

1 atm * 55.2 L = n * 0.08206 atm.L/mol.K * 298 K

n = 2.256 mol

from reaction,

mol of P4 reacting = (1/6)*moles of Cl2 reacting

= (1/6)*2.256 moles

= 0.376 moles

Molar mass of P4 = 123.88 g/mol

we have below equation to be used:

mass of P4,

m = number of mol * molar mass

= 0.376 mol * 123.88 g/mol

= 46.6 g

Answer: 46.6 g

Feel free to comment below if you have any doubts or if this answer do not work

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