is one correet answer for each quest ing questions by eireling the letter of you

Question

is one correet answer for each quest ing questions by eireling the letter of your answer. There 1. Which of the following gas samples would be most likely to behave ideally under the stated conditions? A) Ar at STP B) CO at 200 atm and 25°C C) SO2 at 2 atm and 0 K D) N2 at 1 atm and-70°C E) H2 at 400 atm and 25 C 2. Which of the following samples will have the greatest average speed at 355 K? A) Kr B) C2Hs C) Cl2 D) CH E) All of these samples will have the same average speed. 3. A balloon filled with hel lium gas at 20°C occupies 4.91 L at 1.00 atm. The balloon is immersed in liquid nitrogen at -196°C, while the pressure is raised to 5.20 atm. What is the volume of the balloon in the liquid nitrogen? A) 0.25 L B) 3.6 L C) 6.7 L D) 97 L 4. How many grams of F2 gas are there in a 5.00-L cylinder at 4.00 x 103 mm Hg and 23°C A) 19.5 g B)41.1 g C) 500 g D) 2.96 x 104 g

Explanation / Answer

1. Answer is Opiton A. Ar at STP

Explanation: Ar at STP will behave ideally, as it is a noble gas among the options, smallest in the given options and has least intermolecular forces making it ideal

2. Answer is Option D. CH4

Explanation: Molecular mass is inversely proportional to the speed. In the given option CH4 has the least molecular mass (16.04 g/mol) which means it has more average speed.

The molecular mass of other substances mentioned in the question are as follows: Kr(83.798g/mol), C2H4(28.05), Cl2 (70 g/mol)

Option E cannot be true. Hence, the answer is CH4

3. Answer is Option A. 0.25 L

(P1V1)/T1=(P2V2)/T2

P1= 1 atm V1= 4.91 Lit, T1= 20 +273 =293 K

P2= 5.20 atm V2=? T2= 196+273 =77 K

(1 x 4.91)/293 =(5.2 x V2)/77

(0.017 x 77)/5.2 = 0.25 L

4. Answer is Option B. 41.1 g

We know that PV = nRT

P= (4.00 x 10^3)/760(For conversion into atm pressure) = 5.26 atm; V= 5 L; n=? R= 0.082057 (gas constant); T= 23+273 =296

5.26 x 5 = n x 0.082057 x 296

26.3/ 24.289 = n

n= 1.082 mol of F2

Molar mass of F2 = 38 g/mol

Mass of F2 = 38 x 1.082 = 41.116 g

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