is the maximum speed at which this car can safely negotiato the turn? (13.1 m/s)
ID: 1580935 • Letter: I
Question
is the maximum speed at which this car can safely negotiato the turn? (13.1 m/s) e the N) 0.0 m'e along this curve, what static friction force is needed to keop the car on the road? (4290 N A pilot of mass m = 72.0 kg executes a loop-the-loop as shown in the figure below. In this maneuver, the aircraft moves in a vertical circle of radius 2.70 km at a constant speed of 225 m/s. (a) On the figure, sketch the free-body diagram for the pilot at the bottom or the loop, and at the top of the loop: TOP BOTTOM (b) What centripetal force is necessary for the pilotjet to make this loop-the-loop at this speed? (1350 N) 2.70 What is the force that the seat exerts on the pilot at (c) the top of the loop, and (d) the bottom of the loop. (644 N, 2060 N)Explanation / Answer
The force that the seat exerts on the pilot
at the top is, F= mv2/r - mg = 135000 - 72*9.81 = 1349293.68 N
at the bottom is F= mv2/r + mg = 135000 + 72*9.81 = 1350706.32 N
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.