A generator produces an alternating current according to the equation I=72sin 11

Question

A generator produces an alternating current according to the equation I=72sin 116(pie)t, where t is time measured in seconds and I is current measured in Amperes. What is the smallest amount of time such that I=36 amperes? I have no idea where to even begin. Please help A generator produces an alternating current according to the equation I=72sin 116(pie)t, where t is time measured in seconds and I is current measured in Amperes. What is the smallest amount of time such that I=36 amperes? I have no idea where to even begin. Please help

Explanation / Answer

i = 2sin116pt given i = 36 thus 36 = 72sin116pt sin116pt = 1/2 = sinp/6 thus 116pt = p/6 t = 1/(6*116) = 1.4milli sec.

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