4. A box contains 6 computer chips. Three are from supplier A, two are from supp

Question

4. A box contains 6 computer chips. Three are from supplier A, two are from supplier B, and one is from supplier C. Two separate chips are randomly and simultaneously chosen from the box. The following events are defined: A: Exactly 1 of the 2 selected is from supplier A AAA B: Exactly 1 of the 2 selected is from supplier B Compute P(A) and P(AUB)- Hint: There are 15 outcomes in the sample space. These should be listed below. Denote the 6 chips as AI, A2, A3, Bl, B2, and Cwhich indicate the different suppliers.

Explanation / Answer

Ans:

Total number of ways to select 2 chips=6C2=15

Number of ways to select one from A=3C1*3C1=9

So,P(A)=9/15

Now,

Number of ways to select one from B=2C1*4C1=8

So,P(B)=8/15

Number of ways to select 1 from A and 1 from B=3C1*2C1=6

P(A and B)=6/15

Hence,

P(A or B)=P(A)+P(B)-P(A and B)

=(9/15)+(8/15)-(6/15)

=11/15

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