A play therapist is interested in testing a new intervention using animal assist
ID: 3061204 • Letter: A
Question
A play therapist is interested in testing a new intervention using animal assisted therapy. The play therapist normally conducts group therapy with her clients who are children aged 6 to 9. To test her hypothesis that the children in the animal assisted therapy group will demonstrate less aggressive behavior after 6 months, she randomly assigns 15 of these children to her new intervention group [animal assisted therapy] and the other 15 children will receive her routine group therapy intervention. Using the data below, determine if the children who are in the animal assisted therapy group demonstrate fewer aggressive behaviors at 6 months, than the children in her normal, routine therapy group using the steps of hypothesis testing. Cite all statistics and use words to explain your findings. Provide a full explanation of your results.
Scores on posttest after 6 months of group therapy. Lower scores indicate fewer incidents of aggressive behavior.
Animal assisted group
Routine therapy group
23
22
19
20
15
18
15
19
11
17
14
14
12
16
17
20
13
18
14
21
11
16
11
12
10
14
12
17
14
15
Animal assisted group
Routine therapy group
23
22
19
20
15
18
15
19
11
17
14
14
12
16
17
20
13
18
14
21
11
16
11
12
10
14
12
17
14
15
Explanation / Answer
Here,
Step 1 : Hypothesis testing
H0 : There is no difference between agression behaviour of children aged 6 to 9 with respect to Animal assisted group and Routine Therapy group. 1 = 2
Ha : There are children who in the animal assisted therapy group demonstrate fewer aggressive behaviors at 6 months as compared to routine therapy group. 1 < 2
Here 1 is animal assisted therapy and 2 is routine therapy group .
Step II :
Significance level of test = 0.05
Step III Critical test value
Here n1 = 15 + 15 -2 = 28 and alpha =0.05
tcritical = t0.05,28 = 1.7011
here if test statistic l t l > tcritical then we will reject the null hypothesis
Step IV : Calculation of test statistic
Here sample mean for animal assisted therapy = x1 = 14.0667
Sample standard deviation s1 = 3.4737
Sample mean for Routine Assisted therapy = x2 = 17.2667
Sample standard deviation s2 = 2.8402
Here pooled standard deviation sp = sqrt [(s12 + s22)/2] = sqrt [3.47372 + 2.84022)/2] = 3.1728
Standard error of sample mean difference se0 = sp * sqrt (1/n1 + 1/n2) = 3.1728 * sqrt(1/15 + 1/15) = 1.1585
Test statistic
t = (x1 - x2)/se0 = (14.0667 - 17.2667)/1.1585 = -2.762
so here,
Step V Conclusion
t > tcritical
so we shall reject the null hypothesis and can conclude that there is signifiant reduction in agression behaviour for children of age 6 to 9 by animal assisted therapy as compared to routine therapy.
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