Dear, What is the correct answer for this question. Please show your work so I c

Question

Dear,

What is the correct answer for this question. Please show your work so I can know.

There is also part D which asks: '' which of the values is more likely to be accurate? Explain.''

Best regards,

13 vou trying to determine the concentration of a protein sample B) and are have parformed a Bradford Assay on it. Uso the calibration curve below to help you answer the following questions Calibration curvo for aSA protain ntandard o o 02 o 6,5 e o r o e o 1 1 1 12 1 14 15 16 Protein Concentration (mghri) You tested the of the original sample and a s" dilution of that sample. The spectrophotome er shows that your original prot sample has an absorbance of 0.85 and the ('ls") diluted sample has an absorbance of0.21 a. Calculate how much of the original protein sample you would use to make 1ml of the 's" dilution. (1 b What is the concentration of your original pro n sample? (1 mark) c. What is the concentration of the diluted sample? (1 mark)

Explanation / Answer

a) The original protein has absorbance of 0.85 which for its 1 ml quantity. We are saying 1 ml solution because here is only taking about the net preparation of 1 ml solution. If you take any quantity of original protein it will give same absorbance ever.

The 1/5th of the solution (diluted) has an absorbance of 0.21.

So here only 1/5th part of original protein is diluted, the other 4/5th (1-1/5 = 4/5) part is original. That mean we have taken only 4/5 part of 1 ml solution of original protein. So the 4/5th part of 1 ml is:

1 x 4/5 = 0.8 ml and then rest of 0.2 ml water is used to make the solution 1 ml completely.

b and c) The concentration of diluted sample is:

From the graph in question the 0.8 absorbance (y axis) is showing 1.5 mg/ml concentration (at X-axis).

So, 0.85 absorbance or original protein would lies in between of 0.8 and 0.9 of Y-axis and its absorbance is lies in between 1.5 and 1.6 of X-axis which is 1.55mg/ml. This is calculated by enhance the straight line of plot and then making a perpendicular line from 0.85 point of Y-axis to the straight line of plot, this makes an intersection to the straight line of plot. By doing this we count the concentration at X-axis by making a perpendicular line from intersection of previous drawn to X-axis.

So the original protein concentration is 1.55 mg/ml =C1,

The quantity of original protein is used in for the solution is 0.8 ml = V1

The complete quantity of solution after dilution is 1 ml = V2

Now the concentration of sample after dilution is = C2

It is counted by formula C1 x V1 = C2 x V2

So, by putting all values

1.55 x 0.8 = 1 x C2

C2 = 1.24 mg/ml

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