A conducting rod of length L = 32.5 cm slides over two horizontal metal bars wit

Question

A conducting rod of length L = 32.5 cm slides over two horizontal metal bars with a constant speed v to the right through a distance ?x in a time ?t. The entire setup is in a region of uniform magnetic field of magnitude 1.55 T that is directed perpendicular to the rods and out of the page.

A conducting rod of length L = 32.5 cm slides over two horizontal metal bars with a constant speed v to the right through a distance deltax in a time deltat. The entire setup is in a region of uniform magnetic field of magnitude 1.55 T that is directed perpendicular to the rods and out of the page. If the induced emf has a magnitude of 1.00 V, what is the speed with which the rod moves? What is the direction of the induced current in the resistor R?

Explanation / Answer

(1) by for emf = l(v*b)

=> 1 =0.325(v*1.55) (here v*b is vsin(90)*b)

=>v = 1.98m/s

(2) direction of induced current=a to b

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