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A 18 g bullet pierces a sand bag 25 cm thick. If the initial bullet velocity was

ID: 2258486 • Letter: A

Question

A 18 g bullet pierces a sand bag 25 cm thick. If the initial bullet velocity was 57 m/s and it emerged from the sandbag with 29 m/s, what is the magnitude of the friction force (assuming it to be constant) the bullet experienced while it traveled through the bag? A 18 g bullet pierces a sand bag 25 cm thick. If the initial bullet velocity was 57 m/s and it emerged from the sandbag with 29 m/s, what is the magnitude of the friction force (assuming it to be constant) the bullet experienced while it traveled through the bag? 87 N 0.87 N 8.7 N 22 N A 18 g bullet pierces a sand bag 25 cm thick. If the initial bullet velocity was 57 m/s and it emerged from the sandbag with 29 m/s, what is the magnitude of the friction force (assuming it to be constant) the bullet experienced while it traveled through the bag? A 18 g bullet pierces a sand bag 25 cm thick. If the initial bullet velocity was 57 m/s and it emerged from the sandbag with 29 m/s, what is the magnitude of the friction force (assuming it to be constant) the bullet experienced while it traveled through the bag? 87 N 0.87 N 8.7 N 22 N A 18 g bullet pierces a sand bag 25 cm thick. If the initial bullet velocity was 57 m/s and it emerged from the sandbag with 29 m/s, what is the magnitude of the friction force (assuming it to be constant) the bullet experienced while it traveled through the bag? 87 N 0.87 N 8.7 N 22 N A 18 g bullet pierces a sand bag 25 cm thick. If the initial bullet velocity was 57 m/s and it emerged from the sandbag with 29 m/s, what is the magnitude of the friction force (assuming it to be constant) the bullet experienced while it traveled through the bag? 87 N 0.87 N 8.7 N 22 N A 18 g bullet pierces a sand bag 25 cm thick. If the initial bullet velocity was 57 m/s and it emerged from the sandbag with 29 m/s, what is the magnitude of the friction force (assuming it to be constant) the bullet experienced while it traveled through the bag? 87 N 0.87 N 8.7 N 22 N 87 N 0.87 N 8.7 N 22 N

Explanation / Answer

a =Vf^2-Vi^2/2d =29^2-57^2/(2*0.25)

a=4816 m/s^2

f=ma =18*10^-3*4816

f=87 N

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