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A solid circular disk has a mass of 4.97 kg and a radius of 0.128 m. Each of thr

ID: 2190394 • Letter: A

Question

A solid circular disk has a mass of 4.97 kg and a radius of 0.128 m. Each of three identical thin rods has a mass of 0.379 kg. The rods are attached perpendicularly to the plane of the disk at its outer edge to form a three-legged stool (see the figure). Find the moment of inertia of the stool with respect to an axis that is perpendicular to the plane of the disk at its center. (Hint: When considering the moment of inertia of each rod, note that all of the mass of each rod is located at the same perpendicular distance from the axis.)

Explanation / Answer

A solid circular disk has a mass of 1.2 kg and a radius of 0.18 m. Each of three identical thin rods has a mass of 0.18 kg. The rods are attached perpendicularly to the plane of the disk at its outer edge to form a three-legged stool (see the drawing). Find the moment of inertia of the stool with respect to an axis that is perpendicular to the plane of the disk at its center. (Hint: When considering the moment of inertia of each rod, note that all of the mass of each rod is located at the same perpendicular distance from the axis.)

________kg·m2

A solid circular disk has a mass of 1.2 kg and a radius of 0.18 m. Each of three identical thin rods has a mass of 0.18 kg. The rods are attached perpendicularly to the plane of the disk at its outer edge to form a three-legged stool (see the drawing). Find the moment of inertia of the stool with respect to an axis that is perpendicular to the plane of the disk at its center. (Hint: When considering the moment of inertia of each rod, note that all of the mass of each rod is located at the same perpendicular distance from the axis.)

________kg·m2

A solid circular disk has a mass of 1.2 kg and a radius of 0.18 m. Each of three identical thin rods has a mass of 0.18 kg. The rods are attached perpendicularly to the plane of the disk at its outer edge to form a three-legged stool (see the drawing). Find the moment of inertia of the stool with respect to an axis that is perpendicular to the plane of the disk at its center. (Hint: When considering the moment of inertia of each rod, note that all of the mass of each rod is located at the same perpendicular distance from the axis.)

________kg·m2

The moment of inertia of the disc is Md*R²/2. The moment contributed by each rod is Mr*R². The total moment is then

Md*R²/2 + 3*Mr*R²

Md = 1.2 kg Mr = 0.18 kg, R = 0.18 m The moment of inertia of the disc is Md*R²/2. The moment contributed by each rod is Mr*R². The total moment is then

Md*R²/2 + 3*Mr*R²

Md = 1.2 kg Mr = 0.18 kg, R = 0.18 m The moment of inertia of the disc is Md*R²/2. The moment contributed by each rod is Mr*R². The total moment is then

Md*R²/2 + 3*Mr*R²

Md = 1.2 kg Mr = 0.18 kg, R = 0.18 m
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