The position of a particle moving along an x axis is given by x = 17t^2 - 6.0t^3

Question

The position of a particle moving along an x axis is given by x = 17t^2 - 6.0t^3, where x is in meters and t is in seconds.
(a) Determine the position, velocity, and acceleration of the particle at t = 3.0 s.
(b) What is the maximum positive coordinate reached by the particle?
(c) What is the maximum positive velocity reached by the particle?
(d) What is the acceleration of the particle at the instant the particle is not moving (other than at t = 0)?
(e) Determine the average velocity of the particle between t = 0 and t = 3 s.

Explanation / Answer

1.at t=3 x=-9 v=-6 a=-38 2. v=0 at 34/18=1.89secs x=20.22 3. max velocity=16.06 4. accn=-94.56

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