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The position of a SHO as a function of time is givenby x = 3.6 cos(5 t + / 6)whe

ID: 1681852 • Letter: T

Question

The position of a SHO as a function of time is givenby x = 3.6 cos(5 t + / 6)where t is in secondsand x in meters.
(a) Find the period. ____ s Find the frequency. ____ Hz
(b) Find the position at t = 0. ____ m Find the velocity at t = 0. ____ m/s
(c) Find the velocityat t = 3 s. ____ m/s Find the accelerationat t = 3 s. ____ m/s^2
(a) Find the period. ____ s Find the frequency. ____ Hz
(b) Find the position at t = 0. ____ m Find the velocity at t = 0. ____ m/s
(c) Find the velocityat t = 3 s. ____ m/s Find the accelerationat t = 3 s. ____ m/s^2

Explanation / Answer

Given that          x = 3.6 cos(5 t + / 6) Velocity   v = dx / dt = - 3.6 * sin(5t + /6 ) * 5 = - 56.52 sin(5t +/6) Acceleration a = dv / dt = - 887.36 cos (5t +/6) a) T = 2 / = 2 / 5 = 0.4 s       f = 1 / T = 2.5 Hz b) at t = 0 s         x = 3.117 m         v = - 28.26 m/s c) at t = 3 s        v = 28.26 m/s        a = 768.47 m/s2

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