The position of a SHO as a function of time is given by x=3.4cos(5pi/4+pi/6) whe

Question

The position of a SHO as a function of time is given by x=3.4cos(5pi/4+pi/6) where t is in seconds and x in meters.
Part A- find the period. Round to two significant figures. Units are seconds.
Part B-find the frequency. Round to two signficant figures. Units are Hz.
Part C- Find the position at t=0. Round to two signficant figures. Units are meters
Part D-find the velocity at t=0. Found to two signficant figures. Units are m/s
Part E- find the velocity at 1.9 seconds. Two signficant figures. Units are m/s
Part F- find the acceleration at t=1.9 seconds. Two signficant figures. Units are m/s

Explanation / Answer

x=3.4cos((5pi(t)/4)+(pi/6)) , here = 5/4

a)
time period T = 2/ = 1.6 s

b)

frequency    f = 1/T = 0.625 Hz = 0.6Hz (upto 2 significcant figures)

c) Position at t=0

x=3.4 *cos(5*0/4+/6)

x=2.9 m

d)

velocity v = dx/dt = - 3.4 x 5/4 sin(5t/4+/6)

at t = 0 s

v = -6.7 m/s (upto 2 significcant figures)

Please don't forget to rate positively if you found this response helpful. Feel free to comment on the answer if some part is not clear or you would like to be elaborated upon. Thanks and have a good day!

Related Questions

Navigate

• Browse (All)
• Browse T
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.