A softball is hit over a third baseman\'s head with some speed v_0 at an angle t

Question

A softball is hit over a third baseman's head with some speed v_0 at an angle theta above the horizontal. Immediately after the ball is hit, the third baseman turns around and begins to run at a constant velocity V = 7.00 ;{ m m/s}. He catches the ball t=2.00 ;{ m s} later at the same height at which it left the bat. The third baseman was originally standing L=18.0 ; { m m} from the location at which the ball was hit. a. Find v_0. Use g=9.81 ;{ m m}/{ m s}^2 for the magnitude of the acceleration due to gravity.

Express the initial speed numerically in units of meters per second to three significant figures.

b. express the angle thetha in degrees.

express your answer numerically in degrees in three significant figures

Explanation / Answer

a) v_0 (cos ) * 2 = 18 + 7*2 = 32.

v_0 cos = 16

9.81 * 1 = v_0 * sin

tan = .613125

Hence:

v0 = 18.768m/s

b) = 31.513 degree

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.