A sodium hydroxide solution was prepared according to the procedure outlined in

Question

A sodium hydroxide solution was prepared according to the procedure outlined in this week's experiment. This sodium hydroxide solution was standardized by titration against exactly 10 mL of a 0.2830 M hydrochloric acid solution.

In three titrations, the volumes of the sodium hydroxide solution required to reach the equivalence point were 9.65 mL, 9.80 mL, and 9.56 mL.

What is the molarity of your sodium hydroxide solution?

Molarity of NaOH = ( ) M

This sodium hydroxide solution was then used to determine the amount of acetic acid in vinegar. Three titrations of the sodium hydroxide solution against exactly 5.0 mL of vinegar using phenolphthalein indicator required 21.67 mL, 21.49 mL, and 21.75 mL of the sodium hydroxide solution.

What is the molarity of the acetic acid in vinegar?

Molarity of acetic acid in vinegar = ( ) M

Explanation / Answer

1. mean value of volumer of =(9.65 mL +9.80 mL + 9.56 mL) / 3 = 9.67 mL

there molarity = M1v1 = M2v2

M2 = .283 *10 /9.67 M = .293 M

2. Mean volume =[21.67 mL + 21.49 mL +21.75 mL] /3 = 21.637mL

M1v1 = M2v2

M1 = .293 M *5 /21.637 = .0677 M

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