The drive propeller of a ship starts from rest and accelerates at 3.00 x 10-3 ra

Question

The drive propeller of a ship starts from rest and accelerates at 3.00 x 10-3 rad/s2 for 2.90 x 103 s. For the next 1.70 x 103 s the propeller rotates at a constant angular speed. Then it decelerates at 2.50 x 10-3 rad/s2 until it slows (without reversing direction) to an angular speed of 3.20 rad/s. Find the total angular displacement of the propeller.

Explanation / Answer

1 rev/0.5s = 2 rev/s -> 12.57 radians/s = final angular velocity = wf Time required = 10 rad / (average angular velocity wf/2 = 10/6.28 = 1.59 s Angular acceleration = wf/t = 7.9 rad/s^2 The mass and radius of the wheel are not needed to answer the questions, but would be needed for the required torque.

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