An electron (dashed line) is moving with a speed of 10^7 m/s in a magnetic field

Question

An electron (dashed line) is moving with a speed of 10^7 m/s in a magnetic field of 0.5T, as shown at the right. The electrons velocity makes and angle of 37o with the horizontal and B is vertically upward.  What are the magnitude and direction of the force on the electron?   An electron (dashed line) is moving with a speed of 10^7 m/s in a magnetic field of 0.5T, as shown at the right. The electrons velocity makes and angle of 37o with the horizontal and B is vertically upward.  What are the magnitude and direction of the force on the electron?  

Explanation / Answer

F = qvB = 1.6*10-19*10^7*.5*sin(90 - 37) = 6.4 * 10-13 N

direction is towards z axis

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