Light of original intensity I 0 passes through two ideal polarizing filters havi

Question

Light of original intensity I0 passes through two ideal polarizing filters having their polarizing axes oriented as shown in the figure (Figure 1) . You want to adjust the angle ? so that the intensity at point P is equal to I0/18.0.

Light of original intensity I0 passes through two ideal polarizing filters having their polarizing axes oriented as shown in the figure (Figure 1) . You want to adjust the angle ? so that the intensity at point P is equal to I0/18.0. If the original light is linearly polarized in the same direction as the polarizing axis of the first polarizer the light reaches, what should ? be?

Explanation / Answer

Ifinal = Io cos^2 A

Io/10 = Io cos^2 A

cos^2 A = 1/10

cos A = sqrt(1/10)

angle phi = 71.565 degrees

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