Light is entering a polarizer or set of polarizers from the left. Determine the

Question

Light is entering a polarizer or set of polarizers from the left. Determine the relative intensity of the light exiting on the right after passing through all of the polarizers. The dashed vertical lines represent the vertical reference. The solid lines represent either the polarization angle of the light or the transmission angle of the polarizer. CW represents clockwise and CCW represents counterclockwise as viewed from the right looking back to the left along the path of the light.
Full IntensityPartial IntensityZero Intensity Linearly polarized light polarized at an angle 45°CW from the vertical passes through one polarizer with the transmission axis oriented 45° CW relative to the vertical and then through a second polarizer with the transmission axis oriented 45° CW relative to the vertical.

Full IntensityPartial IntensityZero Intensity Vertically polarized light enters from the left and passes first through a polarizer oriented 45°CW from the vertical and the through a polarizer oriented 45° CW.

Full IntensityPartial IntensityZero Intensity Horizontally polarized light passes through a polarizer with the transmission axis oriented vertically and then through a second polarizer oriented 90° relative to the vertical.

Full IntensityPartial IntensityZero Intensity Unpolarized light enters from the left and passes first through a polarizer oriented 45°CCW from the vertical and the through a polarizer oriented 45° CW.

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Explanation / Answer

PART 1)

as light passes from first polariser its intensity gets half

I1 = Io/2

now second polarizer is 90 degree with first one so final intensity will become ZERO

Part 2)

as light passes from first polariser its intensity gets half

I1 = Io/2

now second polarizer is parallel with first one so final intensity will become Io/2

PART 3

as light passes from first polariser its intensity gets half

I1 = Io/2

now second polarizer is 90 degree with first one so final intensity will become ZERO

PART 4)

as light passes from first polariser its intensity gets half

I1 = Io/2

now second polarizer is parallel with first one so final intensity will become Io/2

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