Light is entering a polarizer or set of polarizers from the left. Determine the

Question

Light is entering a polarizer or set of polarizers from the left. Determine the relative intensity of the light exiting on the right after passing through all of the polarizers. The dashed vertical lines represent the vertical reference. The solid lines represent either the polarization angle of the light or the transmission angle of the polarizer. CW represents clockwise and CCW represents counterclockwise as viewed from the right looking back to the left along the path of the light. Linearly polarized light with the plane of polarization vertical enters from the left and passes through a single polarizer with the transmission axis oriented horizontally (90° relative to the vertical). Vertically polarized light passing through polarizer with horizontal transmission axis Unpolarized light enters from the left and passes through a single polarizer with the transmission axis oriented vertically (0° relative to the vertical). Unpolarized light passing through polarizer with vetical transmission axis Linearly polarized light polarized at an angle 45° CW from the vertical enters from the left and passes through a single polarizer with the transmission axis oriented 45° CW relative to the vertical. 45°CW polarized light passing through 45°CW polarizer Unpolarized light enters from the left and passes through one polarizer with the transmission axis oriented 45° CW relative to the vertical and then through a second polarizer with the transmission axis oriented 45° CW relative to the vertical. Unpolarized light passing through two 45°CW polarizers Unpolarized light enters from the left and passes through a single polarizer with the transmission axis oriented horizontally (90° relative to the vertical). Unpolarized light passing through polarizer with horizontal transmission axis Submit Answer Tries 0/10 Options: Full Intensity, Partial Intensity, Zero Intensity

Explanation / Answer

From malus law, I = Iocos^2 (theta)
a) theta = 90
I = I0*0 = 0
zero intensity
b) I = Io/2 [ for unpolarised light]
partial intensity
c) theta = 0
I = I0cos^2 0 = I
Full intensity
d) Intensity of light after passing from the 1st filet = I/2
After second filetr = Icos^2 0 /2 = I/2
Partial intensity
e) I = I/2
Partial intensity

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