Light of original intensity I0 passes through two ideal polarizing filters havin

Question

Light of original intensity I0 passes through two ideal polarizing filters having their polarizing axes oriented as shown in (Figure 1) . You want to adjust the angle so that the intensity at point P is equal to I0/26.

A) If the original light is unpolarized, what should be?

Express your answer in degrees to three significant figures.

B)

If the original light is linearly polarized in the same direction as the polarizing axis of the first polarizer the light reaches, what should be?

Express your answer in degrees to three significant figures.

Explanation / Answer

a) I0 / 26 = I0/2 cos ^ 2 ()

cos = sqroot ( 2/26)= 73.89 degree

b) Io / 26 = Io cos ^ 2 ()

= 78.69 degree

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