Both Parts need to be answered for full points. Please show your work and any eq

Question

Both Parts need to be answered for full points. Please show your work and any equations you used. Thanks!

if you cant read the question I will retype the words here....

Part A

a 75-turn coil of diameter 13.0 cm is placed in a magnetic field, with the field perpendicular to the area spanned by the coil. the field initially has a magnitude of 0.450 T, and is shut iff uniformly to zero in 27.5 ms. Calculate the voltage induced in the coil.

Part B

If the coil above is made of copper wire of diameter 0.45 mm calculate the induced current

Explanation / Answer

we know the induced emf e = d/dt = *R^2*75*0.45*1000/27.5 = 16.289 V

now the total length of the copper wire = 75*2**R = 30.630 m

we know resistivity of copper = 1.68*10^-8

= > the resistanc eof the wire = 1.68*10^-8*30.360/*r^2 = 2.518 Ohm

=> the current in the wire i = 16.289/2.518 = 6.467 A

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