A solenoid is 2m long, has a raduis of R=20 and 10000 turns per merter (N/L=1000

Question

A solenoid is 2m long, has a raduis of R=20 and 10000 turns per merter (N/L=10000) and has a current of 5 amps (CCW as viewed from the top at t = 0) that is changing at a rate of 2 amps/s. a) Use Amperes law to fine the magnetic flux inside the solenoid at t = 0.

****b). Find the magnetic flux as a function of radius and time, enclosed by an imaginary circle of radius r that is centred at the middle of the solenoid and whose normal is parallel to the axis of the solenoid (there are two cases here; one inside and one outside).

Explanation / Answer

Given that current i=5amp number of turns per unit length N/L=10000 then the magnetic field is B=oNi/L                                          =(4 x 10-7 )(10000)(5)                                         =0.0628T radius of the solenoid is R=0.2m so the area is A=R2                         =0.125 m2 hence the magnetic flux is =BA                                             =7.85 x 10-3 Weber As per cramster there should be only one Question per post so please post other Question seperately other wise your post will be kept under abuse
                                                                  =0.125 m2 hence the magnetic flux is =BA                                             =7.85 x 10-3 Weber As per cramster there should be only one Question per post so please post other Question seperately other wise your post will be kept under abuse
                                                                   

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.