A 1090 kg car is pulling a 285 kg trailer. Together, the car and trailer have an

Question

A 1090 kg car is pulling a 285 kg trailer. Together, the car and trailer have an acceleration of 2.08 m/s2 in the forward direction. Neglecting frictional forces on the trailer, determine the following. (Indicate the direction with the sign of your answer. Take the forward direction to be positive.)
(a) the net force on the car
1. N

(b) the net force on the trailer
2. N

(c) the force exerted by the trailer on the car
3. N

(d) the resultant force exerted by the car on the road
magnitude 4. N
direction 5. ° (below the horizontal from the forward direction)

Explanation / Answer

Ft = ma = 285(2.08) = 592.8 N positive direction. c) the force exerted on the trailer by the car is the same force necessary to pull the trailer since every action has an equal and opposite force. Ft=592.8 N negative direction since it is in the opposite direction. d) the net force to pull the car is 2267.2 N and the force of gravity is Fg = Ma = (1090) 9.8 =10682N downward so the resultant force the car exerts on the road is F = (106822+2267.22) = 10919.950N the direction is found by tan = Fg/Fc tan = 10682/2267.2 tan = 4.711   = 78.017 degrees below horizontal and rearward direction.

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