A 100kg ,12.0m long uniform beam is supported in equilibrium by two fulcrums. Th

Question

A 100kg ,12.0m long uniform beam is supported in equilibrium by two fulcrums. The left fulcrum is 1.00 m from the nearer end of the beam and the right fulcrum is 3.00 m from the nearer end of the beam.
(a) What is the magnitude of the force of the left fulcrum on the beam?
(b) What is the magnitude of the force of the right fulcrum on the beam?

A 100kg, 12.0m long uniform beam is supported in equilibrium by two fulcrums. The left fulcrum is 1.00 m from the nearer end of the beam and the right fulcrum is 3.00 m from the nearer end of the beam. What is the magnitude of the force of the left fulcrum on the beam? What is the magnitude of the force of the right fulcrum on the beam?

Explanation / Answer

for equilibrium, sum of forces in vertical direction = zero

FL + W = FR

FL = left force on the beam

FR = right force on the beam

W = weight of the beam = 980 N

Torque anout the end = 0

FL*1 + W*6 - 3*(FR) = 0

Solving the two equations, we get:

FL = 1470 N

FR = 2450 N

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