A spring of force constant k = 50. 0 N/m is attached to a solid wall at the righ

Question

A spring of force constant k = 50.0 N/m is attached to a solid wall at the right sideof the figure. Its left end is at the equilibrium (unstretched) position. A 1.00-kg object slides from the left side of the gure to the right on a surface that has a coefficient of kinetic friction k = 0.250. It has a speed of 3.00 m/s when it makes contact with the spring.The object is then forced back to the left by the spring. Find the distant D to the left of the equilibrium position that the object then comes to rest again.

Explanation / Answer

K E = spring energy+loss in friction a)0.5*1*(3^2)=0.5*50*x^2+1*g*0.25x=0.38 m b)0.5*1*(3^2)=1*g*0.25(2*x+D) 2x+D=1.835 D=1.075m

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