A spring of force constant 275N/m and unstretched length 0.29m is stretched by t

Question

A spring of force constant 275N/m and unstretched length 0.29m is stretched by two forces, pulling in opposite ends of the spring, that increase to 29N. A. How long will the spring now be B. How much work was required to stretch it that distance? A spring of force constant 275N/m and unstretched length 0.29m is stretched by two forces, pulling in opposite ends of the spring, that increase to 29N. A. How long will the spring now be B. How much work was required to stretch it that distance? A spring of force constant 275N/m and unstretched length 0.29m is stretched by two forces, pulling in opposite ends of the spring, that increase to 29N. A. How long will the spring now be B. How much work was required to stretch it that distance?

Explanation / Answer

part(A)

applied force = F = 29 N

force onstant K = 275 N/m

F = K*dx

dx = F/K = 29/275 = 0.1054 m

length of the spring will be = 0.29 + 0.1054 = 0.3954 m

part(B)

W = 0.5*k*dx^2 = 0.5*275*0.1054^2 = 1.53 J   <--------answer

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