A spring is hanging in an equilibrium position. Hanging from thisspring is a 200

Question

A spring is hanging in an equilibrium position. Hanging from thisspring is a 200g mass. Before releasing the mass, it is raised up10 centimeters. The 200g mass moves down and up 34 times in 60seconds.

a) For this oscillation, what's the period?
b) For this oscillation, what's the frequency?
c) For this oscillation, what's the amplitude?
d) At what point is the speed the most/greatest as the massmoves?
e) At what point is the potential energy the most as the massmoves?
f) At what point is the kinetic energy the most as the massmoves?

Explanation / Answer

a)For this oscillation, what's the period?
T = 2(m/k) or T= 60/34 = 1.76 s b) For this oscillation, what's the frequency? f= 1/T= 1/76= 0.57 Hz
c) For this oscillation, what's the amplitude? |A|= 0.10 m
d) At what point is the speed the most/greatest as the massmoves? y(t)=-Acos(t); =2f = 2 (0.57) =3.56 v(t)=Asin(t) Vmax is at t=/2 or aty=0
e) At what point is the potential energy the most as the massmoves? Pmax is at highest point or y = 0.10m atangle of
f) At what point is the kinetic energy the most as the massmoves? Kemax is at P =0 or at angle = /2 or at V=Vmax

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