A spring is connected to the bottom of a rampinclined at an angle of 45 degrees.

Question

A spring is connected to the bottom of a rampinclined at an angle of 45 degrees. In its equilibrium position,the spring is equal to the length of the ramp, L. If the springconstant is 500 N/m and I want to launch a 5 kg ball, 100 meters asmeasured from the base of the ramp, how long must the ramp be if myinitial compression of the spring is equal to 1/2 the length of theramp. AND. friction on the ramp cannot be ignored.... thecoefficient of friction is .25



I get the question and can draw the picture fine. I also understandthat you must calculate the Energy of the spring the Work done byfriction to get a Kinetic energy where you can calculate the vectorvelocity to find the range, but where do i start.


A spring is connected to the bottom of a rampinclined at an angle of 45 degrees. In its equilibrium position,the spring is equal to the length of the ramp, L. If the springconstant is 500 N/m and I want to launch a 5 kg ball, 100 meters asmeasured from the base of the ramp, how long must the ramp be if myinitial compression of the spring is equal to 1/2 the length of theramp. AND. friction on the ramp cannot be ignored.... thecoefficient of friction is .25



I get the question and can draw the picture fine. I also understandthat you must calculate the Energy of the spring the Work done byfriction to get a Kinetic energy where you can calculate the vectorvelocity to find the range, but where do i start.

Explanation / Answer

Anyone have an idea?

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