The figure below shows a cross section across a diameter of a long cylindrical c

Question

The figure below shows a cross section across a diameter of a long cylindrical conductor of radiusa= 2.00 cm carrying uniform current162A. What is the magnitude of the current's magnetic field at the following radial distances?

The figure below shows a cross section across a diameter of a long cylindrical conductor of radiusa= 2.00 cm carrying uniform current162A. What is the magnitude of the current's magnetic field at the following radial distances? (a) 0 T (b)1.50cm T (c) 2.00 cm (wire's surface) T (d)3.75cm T

Explanation / Answer

a = 2.00 cm, I = 162 A
a) r = 0, B = 0
b) r = 1.50 cm < a
B*2r = 0[I/(a2)]*r2

B = 0Ir/(2a2) = 0.00122 T

c) r = a = 2.00 cm

B = 0I/(2r) = 0.00162 T

d) r = 3.75 cm

B = 0I/(2r) = 0.000864 T

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