The figure below shows a bar of mass m = 0.300 kg that can slide without frictio

Question

The figure below shows a bar of mass m = 0.300 kg that can slide without friction on a pair of rails separated by a distance f = 1.20 m and located on an inclined plane that makes an angle 0 = 34.0 degree with respect to the ground. The resistance of the resistor Is R = 1.80 ohm and a uniform magnetic field of magnitude B = 0.500 T Is directed downward, perpendicular to the ground, over the entire region through which the bar moves, with what constant speed v does the bar slide along the rails? m/s

Explanation / Answer

mg sin = iLB (sin(90-))

mg sin = iLB cos

i = mg tan/(LB)

= BLv

i = /R = BLv/R

v = Ri/(BL)

v = R*(mg tan/(LB))/(BL)

= mgR*tan/(L2B2)

= 0.3 * 9.8 * 1.80 * tan 34/(1.2 * 1.2 * 0.5 * 0.5)

= 9.91 m/s

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