A fluid to fluid heat exchanger is used to cool down hot fluid (specific heat =

Question

A fluid to fluid heat exchanger is used to cool down hot fluid (specific heat = 1.9 kJ/kg.K) that is introduced to the exchanger at 165 degrees C and 1.8 kg/sec. The hot fluid is cooled by water (specific heat = 4.2 kJ/kg.K) that is introduced to the heat exchanger at 15 degrees C and 1.2 kg/sec. The cooling water exits the exchanger at 88 degrees C. Find the rate of heat exchange between the hot fluid and water streams. and find the the exit temperature of the hot fluid flow. Show all work, equations and solutions to this problem. Thanks!

Explanation / Answer

Rate of heat exchange = 1.2 x 4.2 x (88-15) = 367.92 KJ/s exit temp of fluid = 367.92 = 1.8x1.9x(165-T) T= 57.42 Degree celsius = 330.42 K

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