I’m trying to solve part B The answers I put was 276,-276,276.59,264,280 I got a

Question

I’m trying to solve part B The answers I put was 276,-276,276.59,264,280 I got all wrong
Part A roblem 3.43 How hard must you pull on the third sope to teep ihe knot from movin The figure (Figure 1) shows three ropes tied together in a knot One of your friends pulls on a rope with 3.0 units of force and another pulls on a second rope with 5.0 units F= 4.4 units of force of force. Submit My Answers Give Up Correct Significant Figures Feedback: Your answer 4.36 unitsofforee was significant figures than required for this part. Part B In what direction must you pull on the third rope to keep the knot from movin 5.0 units of force 0 120 Knot 1280 Submit Incorrect; Try Again 3.0 units of force counterclo My.Answers Give Up

Explanation / Answer

Put the knot at 0,0 and the 3 unit force along the x axis. The 5 unit force goes into the second quadrant

Sum the Forces Horizontally (the two known ones.

3 units * cos(0o) = + 3 units
5 units * cos(120o) = -2.5 units.
Resultant = +3 - 2.5 = 0.5 units.

Sum the forces vertically
3*sin(0o) = 0
5*sin(120o) = 4.33 units
Resultant + 4.33 vertically

Find where you should be.
F = sqrt(Fx^2 + Fy^2)
F = sqrt(4.33^2 + 0.5^2)
F = sqrt(19)
F = 4.35 N

So you must pull with 4.35 units of force.

Now for the angle
The angle = 180 + Tan-1(vertical/horizontal) = 180 + tan-1(4.33/0.5) = 263.4 o from the + x axis.

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