1. Cecil wants to be able to leap tall doghouses in a single bound while wearing
ID: 1769886 • Letter: 1
Question
1. Cecil wants to be able to leap tall doghouses in a single bound while wearing her Super Dog costume. Cecil can almost jump up to the roof of her doghouse now. She believes that if she received a brief upwards force of 1.000-N just as she started to leap that she could make it up onto the roof. Cecil wants to establish a localized magnetic field right at the take-off point (where she is still traveling horizontally) to help her achieve this. She is going to add 10.00nC of charge on the fake cloud attached to her costume. (a) If she runs due north towards the dog house at her maximum speed of 13.42 m/s, help Cecil estimate the magnitude and determine the direction of the external magnetic field that would result in a sufficient, albeit brief magnetic force? (You can ignore the vertical component of Earth's magnetic field). (b) Since the world record for greatest magnetic field is 91.4T, is the field that you and Cecil calculated a realistic option? (c) Hmm, now that we have made the mistake of telling her that there is a world record for magnetic field magnitude, Cecil is determined to break it. She has built a current loop out of a hula-hoop having a diameter of 71-cm. How much current would she need to pass through the loop to produce a 91.5T field at the center of the loop? (Hint. It would be a lot easier and cheaper to get Cecil a trampoline.)Explanation / Answer
Given,
F = 1 N ; v = 13.42 m/s ; q = 10 nC
Since Cecil has got charge, she can be modelled as a moving charge and we know that the moving charge in a magnetic field experience a magnetic force of magnitude:
F = q v B
B = F/q v = 1/10 x 10^-9 x 13.42 = 7.45 x 10^6 T
Hence, B = 7.45 x 10^6 T
b)No its not a realistic option and practically possible.
c)d = 71 cm => R = 71/2 = 35.5 cm = 0.355 m
We know that the magnetic field of current loop is given by:
B = u0 I/2 R
I = 2 B R/u0
I = 2 x 91.5 x 0.355/4 x 3.14 x 10^-7 = 5.17 x 10^7 A
Hence, I = 5.17 x 10^7 A
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