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1. Carbonated beverages get their effervescence from dissolved CO 2 gas. The bit

ID: 857459 • Letter: 1

Question

1. Carbonated beverages get their effervescence from dissolved CO2 gas. The bite comes from the acidic nature of the beverage resulting from the following reaction.

3. Aluminum hydroxide, Al(OH)3, is insoluble. Determine the molar solubility of aluminum hydroxide in neutral rain.

1. Carbonated beverages get their effervescence from dissolved CO2 gas. The bite comes from the acidic nature of the beverage resulting from the following reaction. H2CO3(aq) + H2O(l) * 10-3. What is the pH of a 0.08 M solution of triethylamine? 3. Aluminum hydroxide, Al(OH)3, is insoluble. Determine the molar solubility of aluminum hydroxide in neutral rain. * 10-4M in H2CO3. 2.Triethylamine, (C2H5)3N, is a weak base related to ammonia Determine the pH of a solution that is 5.91

Explanation / Answer

1)

the concentration (molarity) of H3O+ will be 5.91x10-4M

pH = - log [H3O+]

= - log [5.91x10-4]

= 3.228

2)

(C2H5)3N + H2O <==> (C2H5)3NH+ + OH-

Equilibrium equation:
Kb= [HO-][(C2H5)3NH+]/[(C2H5)3N]

[OH-]= [(C2H5)3NH+] = 0.08 M

-log[HO-] = pOH= -log[0.08] = 1.096

14 - pH = pOH

pH = 14-1.096 =12.903

3) Ksp of Al (OH)+3 = 3 x 10-34

Al (OH)+3 = Al+3 + 3OH-

Let "X" equal the molar solubility of Al(OH)+3. Then

[X][3X]3 = 3 * 10-34

27X4 = 3 * 10-34

X4= (1/9 ) * 10-34

X = 6561 *(1e+136) = molar solubility of Al (OH)+3 in neutral rain.