Main question: A projectile is shot from the edge of a cliff125m above ground le

Question

Main question: A projectile is shot from the edge of a cliff125m above ground level with an initial speed of 65.0m/s at anangle of 37 degrees with the horizontal Find the maximum height above the cliff top reached by theprojectile In this question, i was wondering why the g is positive 9.8 inthis part. (and why not negative.) Main question: A projectile is shot from the edge of a cliff125m above ground level with an initial speed of 65.0m/s at anangle of 37 degrees with the horizontal Find the maximum height above the cliff top reached by theprojectile In this question, i was wondering why the g is positive 9.8 inthis part. (and why not negative.)

Explanation / Answer

Max height reached by the projectile is                    H = u2sin2 / 2g                        = (65.0m/s)2(sin237o) /[2(9.8m/s2)]                        = 78.1m above the cliff

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