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Main Menu Contents Grades Course Contents .Cap11. Rodamiento » Cap11 TimerNotesEvaluate Feedback Print Cap11 Points: 2 In traveling to the Moon astronauts aboard the Apollo spacecraft put themselves into a slow rotation in order to distribute the Sun's energy evenly. At the start of their trip, they accelerated from no rotation to 0.5 revolution every minute during a 15-min time interval. The spacecraft can be thought of as a cylinder with a diameter of 8.1 m. Determine the angular acceleration 5 81 8·10"(-4) rad/s"2 Submit Answer Tries 3/50 Previous Tries Determine the radial component of the linear acceleration of a point on the skin of the ship 10 min after it started this acceleration. Subenit Answer Tries o/so Post Discussion Send Feedback

Explanation / Answer

The initial angular velocity i = 0

the final angular velocity f = 0.5 rev/min = 0.0523                             

the time duration is t = 15min = 900s

the radius of the spacecraft r = 8.1/2 = 4.05m

(a) From rotational dynamics

the angular acceleration

           =( f - i )/t

                = 0.0523 / 900

              = 5.81*10-5 rad/s2

(b) The final angular velocity after t = 10.0min

      f = i + t

             = 0 + (5.81*10-5)(600s)

             = 0.0349 rad/s

Therefore the radial acceleration a = r2

       = (4.05)(0.0349)2

       = 0.00493 m/s2

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