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Main Menu Contents Gra Course Contents > ....Assignment 1 -Units and 1D Motion Linear Kinematic-Acceleration Linear Kinematic - Acceleration Part A car is advertised to be able to stop in a distance of 45.0 m from a speed of 85.0 km/hr. What is its acceleration? Submit Answer Tries 0/10 Part B How many g's is this (g = 9.80 m/s2)? Submit Answer Tries 0/10 © 1998-2017 by Florida State University. All rights reser a violation of the Copyright laws and the FSU honor codes. This discussion is closed. ted The contents of this web site are for use by the students enroled in this course only. Any distribution of the contents in whole or in

Explanation / Answer

Given,

Distance, s = 45 m

Initial Speed, u = 85 km/h = 23.61 m/s

Final speed, v = 0 m/s

Applying Newton's 3rd equation of motion,

v2 = u2 + 2as

Acceleration, a = (-23.61)2/ (2 x 45) = -6.20 m/s2

b) g's in this acceleration a = a/ g = 6.20/9.8 = 0.632

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