A turntable of radius 25cm and rotational inertia .0154 kg*m^2is spinning freely
ID: 1756916 • Letter: A
Question
A turntable of radius 25cm and rotational inertia .0154 kg*m^2is spinning freely at 22 rpm about its central axis, with a 19.5-gmouse on its outer edge. The mouse walks from the edge to thecenter. Find: A) The new rotation speed B) Work done by the mouse A turntable of radius 25cm and rotational inertia .0154 kg*m^2is spinning freely at 22 rpm about its central axis, with a 19.5-gmouse on its outer edge. The mouse walks from the edge to thecenter. Find: A) The new rotation speed B) Work done by the mouseExplanation / Answer
Given that the moment of inertia is I = 0.0154 kg.m2 Radius of table is r = 0.25m Initial angular velocity is 1 = 22rpm = 22*2 /60 rad/s= 2.30 rad/s mass of mouse is m = 19.5*10-3kg ------------------------------------------------------------------------------------------ From the conservvation of angular momentum I1*1 = I2*2 (I+ mr2)1 =I*2 2 = (I + mr2)1 / I = ----------- rad/s Then the work done W =(1/2)I112 -(1/2)I222 =---------- J Radius of table is r = 0.25m Initial angular velocity is 1 = 22rpm = 22*2 /60 rad/s= 2.30 rad/s mass of mouse is m = 19.5*10-3kg ------------------------------------------------------------------------------------------ From the conservvation of angular momentum I1*1 = I2*2 (I+ mr2)1 =I*2 2 = (I + mr2)1 / I = ----------- rad/s Then the work done W =(1/2)I112 -(1/2)I222 =---------- JRelated Questions
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