A tug boat pushes an ocean liner through a port by exerting a horizontal force o

Question

A tug boat pushes an ocean liner through a port by exerting a horizontal force of 10, 000N. The water creates a drag force of 2, 500N directed opposite that of the tug boat (effectively, it is acting like a frictional force. The ocean liner is originally at rest and is pushed a distance of 1, 000 m a) How much work was done by the tug boat? How much work was done by the water resistance? b) What was the final velocity of the liner? c) What was the power output by the tug boat? AND What was the power output by water's resistance?

Explanation / Answer

(A) W = F.d = F d cos(theta)

W_tug = (10,000) (1,000) cos(0) = 10 x 10^6 J

w_resistance = (2500) (1000) cos(180) = - 2.5 x 10^6 J

(B) Applying work energy theorem,

net work done = change in KE

(10 x 10^6) + (-2.5 x 10^6) = (m v^2 / 2) - 0

v = sqrt[ 15 x 10^6 / m]

mass of liner is not given, It must be given somwhere.

put m in kg and get v in m/s.

(C) P = F. V

P_tug = 10,0000 sqrt[ 15 x 10^6 / m]

P_water = 2500 sqrt[ 15 x 10^6 / m]

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.